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\(4.\overline{86} - 3.\overline{71}\text{ = ?}\)

  • A.\(1.\overline{6}\)
  • B.\(1.\overline{5}\)
  • C.\(1.\overline{14}\)
  • D.\(1.\overline{15}\)

Answer: D

\(4.\overline{86} = \left(4 + \dfrac{86}{99}\right)\)
\(3.\overline{71} = \left(3 + \dfrac{71}{99}\right)\)
Hence,
\(4.\overline{86} - 3.\overline{71} \\~\\= \left(4 + \dfrac{86}{99}\right) - \left(3 + \dfrac{71}{99}\right)\\~\\ = \left( 1 + \dfrac{15}{99}\right)\\~\\ = 1.\overline{15}\)

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