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Discussion

Find the H.C.F. of 54, 288, 360

  • A.18
  • B.36
  • C.54
  • D.108

Answer: A

Using factorization method,
\(18 = 2 \times 3^2\)
\(288 = 2^5 \times 3^2\)
\(360 = 2^3 \times 3^2 \times 5\)
So H.C.F. will be minimum term present in all three,
i.e. \(2 \times 3^2 = 18\)

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