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# Discussion

The sum of three consecutive integers is 102. Find the lowest of the three?

• A.40
• B.53
• C.29
• D.33

Three consecutive numbers can be taken as $$(P - 1), P, (P + 1)$$
So, $$(P - 1) + P + (P + 1) = 102$$
$$3P = 102 => P = 34$$
The lowest of the three $$= (P - 1) = 34 - 1 = 33$$

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