The sum of the two digits of a number is 10. If the number is subtracted from the number obtained by reversing its digits, the result is 54. Find the number?

**Answer: **B

Any two digit number can be written as \((10P + Q)\), where \(P\) is the digit in the tens place and \(Q\) is the digit in the units place.

\(P + Q = 10\) ----- (1)

\((10Q + P) - (10P + Q) = 54\)

\(9(Q - P) = 54\)

\((Q - P) = 6\) ----- (2)

Solve (1) and (2) \(P = 2\) and \(Q = 8\)

The required number is \(= 28 \)

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