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# Discussion

If x is a whole number, then $$x^{2}(x^{2}-1)$$ is always divisible by:

• A.12
• B.24
• C.12-x
• D.multiple of 12

Answer: A

Putting x=2, we get $$2^{2}(2^{2}-1) = 12$$. So, $$x^{2}(x^{2}-1)$$ is always divisible by $$12$$

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