When a number is divided by 17, the remainder is 9. When the same number is divided by 23, the remainder is 4. Find the number?

**Answer: **B

\(x = 17p + 9\) and \(x = 23q + 4\)

i.e. \(17p + 9 = 23q + 4\)

Therefore, \(q = \frac{(17p + 5)}{23}\)

Least value of p for which q is a whole number is \(p = 20\)

\(x = 17p + 9\)

\(= 17 \times 20 + 9\)

\(= 349\)

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